If the surface tension of solution of soap in water is 35 dyne/cm, calculate the work done to form an soap bubble of diameter 14 mm with that solution

If the surface tension of solution of soap in water is 35 dyne/cm, cal

1.	If the surface tension of solution of soap in water is 35 dyne/cm, calculate the work done to form an soap bubble of diameter 14 mm with that solution
Answer» <html><body><p></p>Solution :Surface tension `S=35` dynes `cm^(-1)=0.035Nm^(-1)` <br/> Radius of the bubble `(<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> )=(14mm)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)=7mm` <br/> `=<a href="https://interviewquestions.tuteehub.com/tag/7xx10-1922528" style="font-weight:bold;" target="_blank" title="Click to know more about 7XX10">7XX10</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)m` <br/> `W=A(S)=8pir^(2)S` <br/> `implies W=8xx(22)/(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>)xx49xx10^(-6)xx0.035` <br/> `W=4.312xx10^(-6)J`</body></html>