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| 1. |
If the temperature and pressure of a gas is doubled the mean free path of the gas molecules |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>remains same <br/>doubled <br/>tripled <br/>quadruples</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/mean-1091459" style="font-weight:bold;" target="_blank" title="Click to know more about MEAN">MEAN</a> <a href="https://interviewquestions.tuteehub.com/tag/free-465311" style="font-weight:bold;" target="_blank" title="Click to know more about FREE">FREE</a> path of the <a href="https://interviewquestions.tuteehub.com/tag/molecule-563028" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULE">MOLECULE</a> <br/> `gamma=(kT)/(sqrt2pid^(2)P` <br/> If T and P are double, `gamma=(2kT)/(sqrt2pid^(2)(2P))=(kT)/(sqrt2pid^(2)P)`</body></html> | |