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If the two sides of a pair of opposite sides of a cyclic quadrilateral are equal, prove that its diagonals are equal. |
Answer» Given that, ABCD is cyclic quadrilateral in which AB = DC To prove : AC = BD Proof : In ΔPAB and ΔPDC, AB = DC (Given) ∠BAP = ∠CDP (Angles in the same segment) ∠PBA = ∠PCD (Angles in the same segment) Then, ΔPAB = ΔPDC ... (i) (By c.p.c.t) PC = PB ... (ii) (By c.p.c.t) Adding (i) and (ii), we get PA + PC = PD + PB AC = BD |
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