1.

If the two sides of a pair of opposite sides of a cyclic quadrilateral are equal, prove that its diagonals are equal.

Answer»

Given that,

ABCD is cyclic quadrilateral in which AB = DC 

To prove : 

AC = BD 

Proof : 

In ΔPAB and ΔPDC, 

AB = DC (Given) 

∠BAP = ∠CDP 

(Angles in the same segment) 

∠PBA = ∠PCD 

(Angles in the same segment) 

Then,

 ΔPAB = ΔPDC ... (i)

(By c.p.c.t)

PC = PB ... (ii)

(By c.p.c.t)

Adding (i) and (ii), we get 

PA + PC = PD + PB 

AC = BD



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