1.

If the value of n(n2 – 1) is six times the value of Σd2, then what is the value of r?

Answer»

n(n2 – 1) = 6Σd2

Now, r = 1 –\( \frac{6Σd^2}{n(n^2−1)}\)

Putting n(n2 – 1) = 6Σd2

\(r = 1 – \frac{6Σd^2}{6Σd^2}\)

∴ r = 1 – 1 = 0
Hence, the value of r is ‘0’.



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