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If the value of n(n2 – 1) is six times the value of Σd2, then what is the value of r? |
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Answer» n(n2 – 1) = 6Σd2 Now, r = 1 –\( \frac{6Σd^2}{n(n^2−1)}\) Putting n(n2 – 1) = 6Σd2 \(r = 1 – \frac{6Σd^2}{6Σd^2}\) ∴ r = 1 – 1 = 0 |
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