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If the velocity v of particle moving along a straight line decreases linearly with its displacement s from `20 ms^(-1)` to a value approaching zero at s = 30 m, then acceleration of the particle at v=10ms^(-1)` is A. `(2)/(3)ms^(-2)`B. `-(2)/(3)ms^(-2)`C. `(20)/(3)ms^(-2)`D. `-(20)/(3)ms^(-2)` |
Answer» Correct Answer - D `a=upsilon((d upsilon)/(ds))=(10)(-(20)/(30))=-(20)/(3)ms^(-2)` |
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