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If the `Zn^(2+)//Zn` electrode is diluted to 100 times then the change in e.m.f.A. Increase of 59 mVB. Decrease of 59 mVC. Increase of 29.5 mVD. Decrease of 29.5 mV |
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Answer» Correct Answer - A `E_(cell)=(0.059)/(n)log((1)/(C))=-(0.059)/(2)log((1)/(100))` `=-(0.059)/(2)(-2)=0.059V=59mV`. (increase) |
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