If thenA. `a=b`B. `K_(2)=K_(1)^(2)`C. `a=2b`D. `b=a^(2)`

1.	If thenA. `a=b`B. `K_(2)=K_(1)^(2)`C. `a=2b`D. `b=a^(2)`
Answer» Correct Answer - a,b `K_(1)=([C][D])/([A][B])` and `K_(2)=([C]^(2)[D]^(2))/([A][B])` Also, `E^(c-)` is independent of stoichiometry.

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If thenA. `a=b`B. `K_(2)=K_(1)^(2)`C. `a=2b`D. `b=a^(2)`

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