If `theta_1` and `theta_2` be the apparent angles of dip observed in two vertical planes at right angles to each other, then the true angle of dip `theta` is given byA. `cot^2theta=cot^2theta_1+cot^2theta_2`B. `tan^2theta=tan^2theta_1+tan^2theta_2`C. `cot^2theta=cot^2theta_1-cot^2theta_2`D. `tan^2theta=tan^2theta_1-tan^2theta_2`

If `theta_1` and `theta_2` be the apparent angles of dip observed in t

1.	If `theta_1` and `theta_2` be the apparent angles of dip observed in two vertical planes at right angles to each other, then the true angle of dip `theta` is given byA. `cot^2theta=cot^2theta_1+cot^2theta_2`B. `tan^2theta=tan^2theta_1+tan^2theta_2`C. `cot^2theta=cot^2theta_1-cot^2theta_2`D. `tan^2theta=tan^2theta_1-tan^2theta_2`
Answer» Here, `tan theta_1=(V)/(H_1)` and `tan theta_2=(V)/(H_2)` and `tan theta=V/H` `:. H_1=V cot theta_1, H_2=Vcot theta_2, H=Vcot theta` As `H^2=H_1^2+H_2^2` `:. V^2cot^2theta=V^2cot^2theta_1+V^2cot^2theta_2` Hence `cot^2theta=cot^2theta_1+cot^2theta_2`

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