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If three parabols touch all the lines x = 0, y = 0 and x +y =2, then maximum area of the triangle formed by joining their foci is |
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Answer» `sqrt(3)` Hence, foci must be the VERTICES of an equilateral triangle inscribed in the circumcircle. So, area `= (sqrt(3))/(4) (sqrt(3)sqrt(2))^(2) = (3sqrt(3))/(2)`. |
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