1.

If three parabols touch all the lines x = 0, y = 0 and x +y =2, then maximum area of the triangle formed by joining their foci is

Answer»

`sqrt(3)`
`sqrt(6)`
`(3sqrt(3))/(4)`
`(3sqrt(3))/(2)`

SOLUTION :Let ABC be a triangle whose sides are `x =0, y =0` and `x +y = 2`. Since, the parabols TOUCH the side, so foci must lie on CIRCUMCIRCLE of the triangle ABC whose radius is `sqrt(2)`. Now, foci form a triangle of maximum area.
Hence, foci must be the VERTICES of an equilateral triangle inscribed in the circumcircle.
So, area `= (sqrt(3))/(4) (sqrt(3)sqrt(2))^(2) = (3sqrt(3))/(2)`.


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