1.

If two 14-sided dice one is red and one is blue are rolled, find the probability that a 3 on the red die, a 5 on the blue die are rolled.(a) \(\frac{4}{167}\)(b) \(\frac{3}{197}\)(c) \(\frac{5}{216}\)(d) \(\frac{1}{196}\)This question was posed to me during an interview for a job.My enquiry is from Multiplication Theorem on Probability in section Discrete Probability of Discrete Mathematics

Answer»

The correct OPTION is (b) \(\frac{3}{197}\)

The best EXPLANATION: Using the rule of product, there are 196 possible combinations of rolls. Since having the red die = 3 and the BLUE die = 5 are one of the 196 combinations, the REQUIRED probability is \(\frac{1}{14}*\frac{1}{14} = \frac{1}{196}\).



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