If two different numbers are taken from the set `(0, 1, 2, 3. 10):` then the probability that their sum as well as absolute difference are both multiple of 4 are (a) `14/45` (b) `7/55` (c) `6/55` (d) `12/55`

If two different numbers are taken from the set `(0, 1, 2, 3. 10):` th

1.	If two different numbers are taken from the set `(0, 1, 2, 3. 10):` then the probability that their sum as well as absolute difference are both multiple of 4 are (a) `14/45` (b) `7/55` (c) `6/55` (d) `12/55`
Answer» There are `4` sets possible with the numbers having difference multiple of `4`. `A = {1,5,9}` `B = {0,4,8}` `C = {2,6,10}` `D= {3,7}` If we do the sum of any two elements of set `A` and set `D`, it is not a multiple of `4`. If we do the sum of any two elements of set `B` and set `C`, it is a multiple of `4`. Now, we have to select `2` elements from each of the sets `B` and `C`. It can be done in `2C(3,2)` ways. `:.` Required probability ` = (2C(3,2))/(C(11,2)) = (23)/(11**5) = 6/55`

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If two different numbers are taken from the set `(0, 1, 2, 3. 10):` then the probability that their sum as well as absolute difference are both multiple of 4 are (a) `14/45` (b) `7/55` (c) `6/55` (d) `12/55`

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