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If two equal chords of a circle intersect within the circle, prove that the segments ofone chord are equal to corresponding segments of the other chord. |
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Answer» `AL= LB & CM = MD ` `AB _|_ OL and CD _|_ OM` In `/_ LOX and /_ MOX` `AB= CD & OL= OM` `/_ OLX = /_ OMX = 90^O` `OX= OX `common side in both triangles `/_ LOX ~= /_ MOX` `LX= MX` eqn(1) `AB=CD` eqn (3) `AB/2 = CD/2` `So, BL= CM` eqn(2) add eqn 1 & 2 `LX + BL = MX + CM` `BX = CX` eqn (4) subtract eqn 4 from 3`AB - BX = CD- CX` `AX= DX`hence proved |
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