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If two waves represented by `y_(1)=4sinomegat` and `y_(2)=3sin(omegat+(pi)/(3))` interfere at a point find out the amplitude of the resulting waveA. 7B. 6C. 5D. `3.5` |
Answer» Correct Answer - B Here phase difference `phi=pi//3` So, amplitude of resulting wave `A=sqrt(a_(1)^(2)+a_(2)^(2)+2a_(1)a_(2) cos phi)` `=sqrt(4^(2)+3^(2)+2xx4xx3 cos pi//3)approx 6` |
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