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If `v_1` is the frequency of the series limit of lyman seies, `v_2` is the freqency of the first line of lyman series and `v_3` is the fequecny of the series limit of the balmer series, thenA. `v_1-v_2=v_3`B. `v_1=v_2-v_3`C. `(1)/(v_2)=(1)/(v_1)+(1)/(v_3)`D. `(1)/(v_1)=(1)/(v_2)+(1)/(v_3)` |
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Answer» Correct Answer - A For lyman series `upsilon=Rc[(1)/(1^2)-(1)/(n^2)]` where n=2,3,4,....... for the seires limit of lyman series , `n=oo` `therefore upsilon_1=Rc[(1)/(1^2)-(1)/(oo^2)]=Rc`.........(i) for the first line of lyman series, `n=2` `therefore upsilon_2=Rc[(1)/(1^2)-(1)/(2^2)]=(3)/(4)Rc`........(ii) for balmer series `upsilon=Rc[(1)/(2^2)-(1)/(n^2)]` where n= 3,4,5..... For the series limit of balmer serie , `n=oo` `thereforeupsilon_3=Rc[(1)/(2^2)-(1)/(oo^2)]=(Rc)/(4)`........(iii) from equations (i),(ii),(iii), we get `upsilon_1=upsilon_2+upsilon_3` or `upsilon_1-upsilon_2=upsilon_3` |
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