If we take 44g of `CO_(2)` and 14g of `N_(2)` what will be mole fraction of `CO_(2)` in the mixtureA. `1//5`B. `1//3`C. `2//3`D. `1//4`

If we take 44g of `CO_(2)` and 14g of `N_(2)` what will be mole fracti

1.	If we take 44g of `CO_(2)` and 14g of `N_(2)` what will be mole fraction of `CO_(2)` in the mixtureA. `1//5`B. `1//3`C. `2//3`D. `1//4`
Answer» Correct Answer - C Mole fraction of `CO_(2)=(n_(CO_(2)))/(n_(CO_(2))+n_(N_(2)))=((44)/(44))/((44)/(44)+(14)/(28))=(2)/(3)`.

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If we take 44g of `CO_(2)` and 14g of `N_(2)` what will be mole fraction of `CO_(2)` in the mixtureA. `1//5`B. `1//3`C. `2//3`D. `1//4`

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