1.

if x^(2)+3x+2 lt 0 and f(x)=x^(2)-3x+2, then

Answer»

`0 lt f(x) lt 6`
`f(x) ge (3)/(2)`
`f(x) gt 12`
`f(x)GT0`

Solution :The problem is asking for the range of f(x) values for values of x that satisfy the inequality. FIRST GRAPH the inequality in `Y_(1)`, STARTING with the standardd window and zooming in until the x values for the portion of the graph that falls below the x-axis can be identified as the interval (-2,-1). then enter the formula for f(x0 in `Y_(2)`. although it can be done graphically, the simplest way to find the range of values of f(x) that correspond to `x epsi(-2,-1) ` is to use the TABLE function. deselct `Y_(1)` and enter TBLSET and set TblStart to -2, `DeltaTbl=0.1`, and Indpnt and Depend to Auto. then enter TABLE and observe that the `Y_(2)` values range from 12 to 6 as x ranges from -2 to 1, YIELDING the correct answer, choice E. The greatest integer less tha orr equal to x is int(x) on the graphing calculator. enter abs(x)+int(x) int `Y_(1)`. Return to the home screen, and enter `Y_(1)(-2.5)+Y_(1)(1.5)` to get the correct answer, choice D.


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