1.

If `x` is a real, then the maximum value `(x^2+14x+9)/(x^2+2x+3)``(i)2 (ii)4 (iii)6 (iv) 8`A. 3, 1B. 4, -5C. `0, -oo`D. `oo, -oo`

Answer» Correct Answer - B
Let `y=(x^(2)+14x+9)/(x^(2)+2x+3)`. Then, `x^(2)(y-1)+2x(y-7) + 3y - 9 = 0`
`rArr" "4(y-7)^(2) - 4(y-1)(3y-9) ge 0" "[because "x is real"]`
`rArr" "y^(2) + y - 20 le 0 rArr -5 le y le 4`


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