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If x1, x2, x3, are the roots of the cubic equation x³ + 2x + 6 = 0, prove that S7 = 2(S4 - S6). [Sn = (x1)^n + (x2)^n + (x3)^n]

Answer» If x1, x2, x3, are the roots of the cubic equation x³ + 2x + 6 = 0, prove that S7 = 2(S4 - S6). [Sn = (x1)^n + (x2)^n + (x3)^n]


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