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If x3 + px + q and x3 + qx + p have a common factor, then which of the following is correct ?(a) p + q = 0 (b) p + q – 1 = 0 (c) (p + q + 1) = 0 (d) p – q + 1 = 0 |
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Answer» (c) (p + q + 1) = 0. Let the common factor be x – α, then x = α will make the given expressions zero, i.e., α2 + pα + q = 0 α2 + qα + p = 0 Solving by the rule of cross-multiplication, we have \(\frac{α^2}{p^2-q^2}\) = \(\frac{α}{q-p}\) = \(\frac{1}{q-p}\) From, last two relation, α = 1. ⇒ α2 = \(\frac{p^2-q^2}{q-p}\) ⇒ 1 = – (p + q) ⇒ p + q + 1 = 0. |
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