If `y=x^(x), "find" (dy)/(dx).`

1.	If `y=x^(x), "find" (dy)/(dx).`
Answer» We have, `y=x^(2)` `therefore log y=x log x` On differentiating w.r.t. x, we get `1/y (dy)/(dx)=x/x +log x` `(dy)/(dx)=y+ylog x` `(dy)/(dx)=x^(x)(1+logx)` `(becaue y=x^(3))`

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