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| 1. |
(ii) If sin x =-1/2,COS X = √3/2 ,then find the quardants in which X lies |
| Answer» <html><body><p><strong>Answer:</strong></p><p></p><p><strong>Step-by-step explanation: We <a href="https://interviewquestions.tuteehub.com/tag/know-534065" style="font-weight:bold;" target="_blank" title="Click to know more about KNOW">KNOW</a> that,</strong></p><p><strong>sinx = - 1/2 (<a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a>)</strong></p><p><strong>=> sinx = - (sin 30°)</strong></p><p>=> sinx = sin( 180+ 30) ( <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a>, -sinx = sin(180+x) )</p><p>=> x = sin(180+ 30) </p><p>Therefore, x lies in the 3rd quadrant ( Ans.) </p><p>Now, <a href="https://interviewquestions.tuteehub.com/tag/cosx-936418" style="font-weight:bold;" target="_blank" title="Click to know more about COSX">COSX</a> = √3/2</p><p>=> cosx = cos30°</p><p>=> x = 30°</p><p>=> x = (0 + 30°)</p><p>Therefore, x lies in the 1st quadrant (Ans.)</p><p></p></body></html> | |