In a barometer tube of 1m long and 2cm^(2) cross -section, mercury stands at a height of 75 cm of Hg. When a small amount of oxygen is introduced in the space above the mercury, the level falls by 10 cm . Find the mass of oxygen introduced. ( Room tempetature = 27^(@)C, density of mercury= 13.6 gm/cc, g = 10 ms^(-2) )

In a barometer tube of 1m long and 2cm^(2) cross -section, mercury sta

1.	In a barometer tube of 1m long and 2cm^(2) cross -section, mercury stands at a height of 75 cm of Hg. When a small amount of oxygen is introduced in the space above the mercury, the level falls by 10 cm . Find the mass of oxygen introduced. ( Room tempetature = 27^(@)C, density of mercury= 13.6 gm/cc, g = 10 ms^(-2) )
Answer» <html><body><p></p>Solution :Volume of <a href="https://interviewquestions.tuteehub.com/tag/oxygen-1144542" style="font-weight:bold;" target="_blank" title="Click to know more about OXYGEN">OXYGEN</a> <br/> `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> = <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> xx (100 - 65) xx 10^(-6) = 70 xx 10^(-6) m^(3)` <br/> Pressure of oxygen, P = `rho` gh <br/> `= (13.6 xx 10^(3)) (10) (10 xx 10^(-2)) = 13,6000 Nm^(2)`<br/> <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> oxygen T = 300 K, <br/> `therefore ` mass of oxygen, <br/> m `= (PVM)/(RT ) = 13,600 xx 70 xx 10^(-6) xx 32 xx (10^(-3))/(8.3 xx 300) ` <br/> = 0.012 gm</body></html>