1.

In a compound microscope the object is 1cm from the objective lens. The lenses are 30cm apart and the intermediate image is 5cm from the eyepiece. What magnification is produced?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :As the <a href="https://interviewquestions.tuteehub.com/tag/lenses-1071864" style="font-weight:bold;" target="_blank" title="Click to know more about LENSES">LENSES</a> are 30cm apart and intermediate image is formed 5cm in <a href="https://interviewquestions.tuteehub.com/tag/front-1000768" style="font-weight:bold;" target="_blank" title="Click to know more about FRONT">FRONT</a> of eye lens, <br/> `u_e=5cm and v=L-u_e=30-5=25cm` <br/> Now as in case of compound microscope <br/> `M=m_0 times m_e=-v/u times [D/u_e]` <br/> Here u=1cm and D=25cm <br/> So, `M=-25/1 times [25/5]=-125` <br/>Negative sign impiles that <a href="https://interviewquestions.tuteehub.com/tag/find-11616" style="font-weight:bold;" target="_blank" title="Click to know more about FIND">FIND</a> image is inverted</body></html>


Discussion

No Comment Found