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In a concave mirror, an object is placed at a distance `d_1` from the focus and the real image is formed aat a distance `d_2` from the focus. Then the focal length of the mirror is :A. `sqrt(d_1 d_2)`B. `d_1 d_2`C. `(d_1 + d_2)//2`D. `sqrt(d_1//d_2)` |
Answer» Correct Answer - A Here, `u = -(f + d_1) and v = -(f + d_2)` From `(1)/(u)+(1)/(v)=(1)/(f)` `(1)/(-(f + d_1)) + (1)/(-(f + d_2)) = (1)/(-f)` `(2 f + d_1 + d_2)/((f + d_1)(f + d_2))=(1)/(f)` or `2f^2 + (d_1 + d_2)f = f^2 + d_1 f + d_2 f + d_1 d_2` `f^2 = d_1 d_2` or `f = sqrt(d_1 d_2)`. |
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