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In a conductor, `10^(16)` electrons move from a point A towards point B in 1 milli second. `10^(14)` positive ions move from a point B towards point A in 1 milli second. What is the current in ampere and its direction? Charge on electron = charge on position ion `= 1.6 xx 10^(-19)C`. |
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Answer» Here, `n_(e)=10^(16) , n_("ion")=10^(14) , t=10^(-3)s`, Charge on electron or ion, `q=1.6xx10^(-19)C`. Current, `I=(n_(e) xx q +n_("ion")xxq)/(t)` `(10^(16)xx1.6xx10^(-19)+10^(14)xx1.6xx 10^(-19))/(10^(-3))` `=(10^(16)xx1.6xx10^(-19))/(10^(-3)) =1.6A` The direction of current is from B to A. |
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