In a fully turgid cellA. `Psi_(w)=Psi_(s)+Psi_(rho)`B. `Psi_(w)=` zeroC. `Psi_(w)=-Psi_(s)-Psi_(rho)`D. `Psi_(w)=Psi_(s)=Psi_(rho)`

In a fully turgid cellA. `Psi_(w)=Psi_(s)+Psi_(rho)`B. `Psi_(w)=` zero

1.	In a fully turgid cellA. `Psi_(w)=Psi_(s)+Psi_(rho)`B. `Psi_(w)=` zeroC. `Psi_(w)=-Psi_(s)-Psi_(rho)`D. `Psi_(w)=Psi_(s)=Psi_(rho)`
Answer» Correct Answer - B In case of fully turgid cell, the net movement of water into the cells is stopped. the cell is in equilibrium with the water outside. the water potential in such a case will be zero (0). A cell at full turgor its osmotic potential and pressure potential equal but opposite in sign. Therefore, its water potential will be zero. For example a cell has its `psi_(s)` of - 10 bars and `psi_(p)` fo 10 bar, the resultant water potential will be zero as follows: `psi_(w) = psi_(s) + psi_(p)` `psi_(w) = - `10 bars + 10 bars `psi_(w) = 0` bars

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In a fully turgid cellA. `Psi_(w)=Psi_(s)+Psi_(rho)`B. `Psi_(w)=` zeroC. `Psi_(w)=-Psi_(s)-Psi_(rho)`D. `Psi_(w)=Psi_(s)=Psi_(rho)`

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