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In a hexagon ABCDEF, side AB is a parallel to EF and \angle B : \angle C : \angle D : \angle E=5 : 4 : 2 : 1. FInd \angle B, \angle C, \angle D \text { and } \angle E |
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Answer» As AB || FE, FA becomes the tranversal line cutting parallel lines. So angle A + angle F = 180°. sum of other four angles = 720° - 180°= 540°.So 6 x + 4 x + 2 x + 3 x = 15 x = 540°.x = 36°. Angles B C D E are: 216°, 144°, 72°, 108° |
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