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In a hydrogen atom, the electron moves in an orbit of radius `0*5 Å`, making `10^(16)rps`. Calculate the magnetic moment associated with the orbital motion of electron. |
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Answer» Here, `r=0*5Å=0*5xx10^(-10)m`, `v=10^(16)rps, M=?` Charge on electron, `e=1*6xx10^(-19)C` Equivalent current, `I=e/T=ev` Area of the orbit, `A=pir^2` As `M=IA` `:. M=ev(pir^2)=1*6xx10^(-19)xx10^(16)xx3*14xx(0*5xx10^(-10))^2` `=1*256xx10^(-23)Am^2` |
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