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In a reaction `2A to ` Products, the concentration of A decreases from `0.5 mol I^(-1)` to `0.4 mol L^(-1)` in 10 minutes. Calculate the rate during this interval. |
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Answer» `2A to` products `0.5 -0.4` mol lit rate `prop [A]^(2)` rate `=(-1)/(2) (d)/(dt) [A]=1/2 [((0.5-0.4))/(10)]=0.5xx10^(-2)` rate `=5xx10^(-3) mol Lit ^(-1) min ^(-1)` |
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