 
                 
                InterviewSolution
 Saved Bookmarks
    				| 1. | In a reaction, if half of the double bond is broken and two new bonds are formed, this is a case ofA. EliminationB. AdditionC. DisplacementD. Rearrangement | 
| Answer» Correct Answer - B e.g. `CH_2=CH_2+Br_2 to undersetunderset(Br)(|)CH_2-undersetunderset(Br)(|)CH_2` Half of the double bond is broken. Its means `pi` bond is broken while sigma bond is retained also two new C-Br bonds are formed | |