1.

In a reaction, if half of the double bond is broken and two new bonds are formed, this is a case ofA. EliminationB. AdditionC. DisplacementD. Rearrangement

Answer» Correct Answer - B
e.g. `CH_2=CH_2+Br_2 to undersetunderset(Br)(|)CH_2-undersetunderset(Br)(|)CH_2`
Half of the double bond is broken. Its means `pi` bond is broken while sigma bond is retained also two new C-Br bonds are formed


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