Saved Bookmarks
| 1. |
In a reaction, if half of the double bond is broken and two new bonds are formed, this is a case ofA. EliminationB. AdditionC. DisplacementD. Rearrangement |
|
Answer» Correct Answer - B e.g. `CH_2=CH_2+Br_2 to undersetunderset(Br)(|)CH_2-undersetunderset(Br)(|)CH_2` Half of the double bond is broken. Its means `pi` bond is broken while sigma bond is retained also two new C-Br bonds are formed |
|