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In a reaction x + y + z2 → xyz2 , identify the limiting reagent if any, in the following reaction mixtures. (a) 200 atoms of (x + 200) atoms of (y + 50) molecules of z2 (b) 1 mol of (x + 1) mol of (y + 3) mol of z2 (c) 50 atoms of (x + 25) atoms of (y + 50) molecules of z2(d) 2.5 mol of (x + 5) mol of (y + 5) mol of z2 |
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Answer» (a) 200 atoms of (x + 200) atoms of (y + 50) molecules of z2 According to the reaction, 1 atom of x reacts with one atom of y and one molecule of z to give product. In the case (a) 200 atoms of x, 200 atoms of y react with 50 molecules of z2 (4 part) i.e. 50 molecules of z2 react with 50 atoms of x and 50 atoms of y. Hence z is the limiting reagent. (b) 1 mol of (x + 1) mol of (y + 3) mol of z2 According to the equation, 1 mole of z2 only react with one mole of x and one mole of y. If 3 moles of z2 are there, z2 is limiting reagent. (c) 50 atoms of (x + 25) atoms of (y + 50) molecules of z2 25 atoms of y react with 25 atoms of x and 25 molecules of z2 . So y is the limiting reagent. (d) 2.5 mol of (x + 5) mol of (y + 5) mol of z2 2.5 mol of x react with 2.5 mole of y and 2.5 mole of z2 . So x is the limiting reagent. |
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