In a solution of `CuSO_(4)` how much time will be required to preciitate 2 g copper by 0.5 ampere current?A. 12157.48secB. 102secC. 510secD. 642sec

In a solution of `CuSO_(4)` how much time will be required to preciita

1.	In a solution of `CuSO_(4)` how much time will be required to preciitate 2 g copper by 0.5 ampere current?A. 12157.48secB. 102secC. 510secD. 642sec
Answer» Correct Answer - A `Cu^(3+)+underset(2"mole 2F")(2e^(-))rarrunderset("1mole" 63.4gm)(Cu)` To deposit 63.5gm of copper, electricity needed `=2xx96500C` To d eposit 2 gm of copper, electricity needed `=2xx(96500)/(63.5)xx2=6078.74C` `Q=6078.74C` `1=0.5` ampere Q=It t(in seconds)`=(Q)/(1)=(6078.74)/(0.5)=12157.48s`

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In a solution of `CuSO_(4)` how much time will be required to preciitate 2 g copper by 0.5 ampere current?A. 12157.48secB. 102secC. 510secD. 642sec

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