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In an isolated parallel plate capacitor of capacitancee `C`, the four surface have chrges `Q_(1),Q_(2),Q-(3)` and `Q_(4)` as shown. The potential difference between the plates is A. `(Q_(1)+Q_(2)+Q_(3)+Q_(4))/(2C)`B. `(Q_(2)+Q_(3))/(2C)`C. `(Q_(2)-Q_(3))/(2C)`D. `(Q_(1)+Q_(4))/(2C)` |
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Answer» Correct Answer - C Facing surface have equal and opposite charges `Q_(3)=-Q_(2)` charge on capacitor `Q_(2) or -Q_(3)` `V=(Q-(20))/(c)` `V=(-Q_(3))/(c)`….(ii) `(i)+(ii)` `2V=(Q_(2)-Q_(3))/(c)impliesV=(Q_(2)-Q-930)/(2C)` |
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