In basic medium, CrO2−4 oxidises S2O2−3 to form Cr(OH)−4 and SO – InterviewSolution

InterviewSolution

1.	In basic medium, CrO2−4 oxidises S2O2−3 to form Cr(OH)−4 and SO2−4. How many mL(nearest integer) of 0.154 M CrO2−4 are required to react with 40.0 mL of 0.246 M S2O2−3?[Hint:0.0154 M=0.154×3 N CrO2−4 and 0.246 M=0.246×8 N S2O2−3]
Answer» In basic medium, $C r O_{4}^{2 -}$ oxidises $S_{2} O_{3}^{2 -}$ to form $C r (O H)_{4}^{-}$ and $S O_{4}^{2 -}$ . How many mL(nearest integer) of $0.154 M$ $C r O_{4}^{2 -}$ are required to react with $40.0 mL$ of $0.246 M$ $S_{2} O_{3}^{2 -}$ ? $[Hint : 0.0154 M = 0.154 \times 3 N C r O_{4}^{2 -} and 0.246 M = 0.246 \times 8 N S_{2} O_{3}^{2 -}]$

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