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In fig, if A, B, C and D are vertices of cyclic quadrilateral, then will be :(A) 70°(B) 35°(C) 110°(D) 100° |
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Answer» Answer is (C) 110° ∵ ∠CBA + 70° = 180° (linear pair) ∠CBA = 180° – 70° = 110° ∵ ABCD is cyclic quadrilateral We know that sum of opposite angles of cyclic quadrilateral is 180° Thus, ∠CBA + ∠CDA = 180° ⇒ 110° + ∠CDA = 180° ⇒ ∠CDA = 180° – 110° = 70° But ∠x + ∠CDA = 180° (linear pair) ∠x + 70° = 180° ∠x = 180° – 70° = 110° |
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