1.

In Fig. if AP = PB, thenA. AC = AB B. AC = BC C. AQ = QC D. AB = BC

Answer»

Answer is B.  AC = BC

Given: 

AP = PB 

Property: If two tangents are drawn to a circle from one external point, then their tangent segments (lines joining the external point and the points of tangency on circle) are equal. 

By the above property, 

AP = AQ (tangent from A) 

BR = BP (tangent from B) 

CQ = CR (tangent from C) 

Clearly, 

AP = BP = BR 

AQ = AP = BR 

Now, 

AQ + QC = BR + RC 

⇒ AC = BC [∵AC = AQ + QC and BC = BR + RC] 

Hence, AC = BC



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