In figure, if `angleOAB=40^(@),"then"angleACB " is equal to "` A. `50^(@)`B. `40^(@)`C. `60^(@)`D. `70^(@)`

In figure, if `angleOAB=40^(@),"then"angleACB " is equal to "` A. `50^

1.	In figure, if `angleOAB=40^(@),"then"angleACB " is equal to "` A. `50^(@)`B. `40^(@)`C. `60^(@)`D. `70^(@)`
Answer» Correct Answer - A `"In "DeltaOAB, OA=OB ["both are the radius of a circle"]` `:.angleOAB=angleOBArArrangleOBA=40^(@)` [angle opposite to equal sides are equal] Also, `angleAOB+angleOBA+angleBAO=180^(@)` [by angle sum property of a triangle] `:.angleAOB+40^(@)+40^(@)=180^(@)` `rArr angleAOB=180^(@)-80^(@)=100^(@)` We know that, in a circle, the angle subtended by an arc at the centre is twice the angle subtended by it at the remaining part of the circle. `:. angle AOB=2angleACB` `rArr 100^(@)=2angleACB` `:. angleACB=100^(@)/2=50^(@)`

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In figure, if `angleOAB=40^(@),"then"angleACB " is equal to "` A. `50^(@)`B. `40^(@)`C. `60^(@)`D. `70^(@)`

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