In resonance tube experiment , the velocity of sound is given by `v = 2 f_(0) ( l_(2) - l_(1))` . We found `l_(1)=25.0 cm` and `l_(2)=75.0 cm`. If there is no error in frequency, what will be the maximum permissible errror in the speed of sound ? (Take `f_(0) = 325 Hz`)

In resonance tube experiment , the velocity of sound is given by `v =

1.	In resonance tube experiment , the velocity of sound is given by `v = 2 f_(0) ( l_(2) - l_(1))` . We found `l_(1)=25.0 cm` and `l_(2)=75.0 cm`. If there is no error in frequency, what will be the maximum permissible errror in the speed of sound ? (Take `f_(0) = 325 Hz`)
Answer» `V = 2f_(0)(l_(2) - l_(1))` `(dV) = 2f_(0) ( dl_(2) - dl_(1))` `(dV)_(max) = max of [ 2f_(0) (+- Delta l_(2) +- Deltal_(2)]` `l_(1) = 25.0 cm rArr l_(1) = 0.1 cm` ( place value of last number) `l_(1) = 75.0 cm rArr l_(2) = 0.1 cm` ( place value of last number) So the maximum permissible error in the speed of sound `(dV)_(max)` `= 2( 325 Hz) ( 0.1 cm + 0.1 cm ) = 1.3 m s^(-1)` Value of `V = 2f_(0) (l_(2) - l_(1) = 2(325 Hz) (75.0 cm - 25.0 cm)` ` = 325 m s^(-1)` So `V = (325 +- 1.3) m s^(-1)`.

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In resonance tube experiment , the velocity of sound is given by `v = 2 f_(0) ( l_(2) - l_(1))` . We found `l_(1)=25.0 cm` and `l_(2)=75.0 cm`. If there is no error in frequency, what will be the maximum permissible errror in the speed of sound ? (Take `f_(0) = 325 Hz`)

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