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In `SN^2`, solvolysis `RX` in which the solvent is a nucleophile, what is the order and molecularity of the reaction ?A. First order , unimolecularB. First order , bimolecularC. Second order , bimolecularD. Pseudo first-order , bimolecular

Answer» Correct Answer - D
`SN^2` solvolysis reaction in bimolecular and the rate law is :
Rate `= K[RX] ["Solvent"]`
Since the concentration of the solvent is very large and exceeds the amount of `RX`, therefore, its concentration is constant. Hence the reaction will follow pseudo first-order rate law.


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