In solid `CuSO_(4).5H_(2)O`A. `Cu^(2+)` ion is coordinate bonded to four water moleculesB. One `H_(2)O` molecule is `H-` bondedC. It has four types of bonds, Ionic, covalent, coordinate and H- bondD. Five molecules of `H_(2)O` are coordinate bonded to `Cu^(2+)`

In solid `CuSO_(4).5H_(2)O`A. `Cu^(2+)` ion is coordinate bonded to fo

1.	In solid `CuSO_(4).5H_(2)O`A. `Cu^(2+)` ion is coordinate bonded to four water moleculesB. One `H_(2)O` molecule is `H-` bondedC. It has four types of bonds, Ionic, covalent, coordinate and H- bondD. Five molecules of `H_(2)O` are coordinate bonded to `Cu^(2+)`
Answer» Correct Answer - A,B,C

Discussion

No Comment Found

Related InterviewSolutions

`K_(2)CrO_(4)` is converted to `K_(2)Cr_(2)O_(7)` byA. conc. `H_(2)SO_(4)`B. KOHC. `K_(2)CO_(3)`D. `KNO_(3)`
A compound `(A)` is used in paints instead of salts of lead. . Compound(A) is obtained when a white compound `(B)` is strongly heated . Compound `(B)` is insoluble in water but dissolves in sodium hydroxide forming a solution of compound `(C )` the compounds `(A)` on heating with coke gives a metal `(D)` and a gas `(E)` which burns with blue flame . `(B)` also dissolves in ammonium sulphate solution mixed with ammonium hydroxide. solution of compound `(A)` in dilute `HCl` gives a bluish white//white precipitate `(F)` with excess of `(F)` with excees of `K_(4)[Fe(CN)_(6)]` identify `(A)` to `(F)` and explain the reactions.A. Solution (F)B. Solution (H)C. A and B bothD. None of these
Number of salts among the following that will give metal on heating `Zn(NO_(3))_(2),AgNO_(3),Cu(NO_(3))_(2),Hg(NO_(3))_(2)`
Match the following `:`A. `{:("Compound",,"Characteristics",),((A)TiCl_(4),,(p)"Liquid at room temperature",):}`B. `{:("Compound",,"Characteristics",),((B)CaCl_(2),,(q)"Has the highest MP among the compounds given",):}`C. `{:("Compound",,"Characteristics",),((C)FeCl_(3),,(r)"Aqueous solution is acidic",):}`D. `{:("Compound",,"Characteristics",),((D) ZnCl_(2),,(s)"Undergoes hydrolysis",),(,,(t)"Solid at room temperature",):}`
The oxidation state of chrominium in the final product formed in the reaction between `KI` and acidified potassium dichromate soluttion is
`(NH_(4))_(2)Cr_(2)O_(7)overset(Delta)rarrN_(2)+4H_(2)O+X` ( Chromium compound), oxidation state of chromium that changes from `(NH_(4))_(2)Cr_(2)O_(7)` to X isA. 3B. 4C. 5D. -3
Match the reactions in Column I with nature of the reactions `//` type of the products in Column II. A. `MnO_(4)^(2-)+H^(+)rarr" "(p)` One of the products of transition element is paramagneticB. `Cu^(+)(aq)rarr" "(q)` Disproportionation reaction.C. `Cr_(2)O_(7)^(2-)(s)+H^(+)("conc.")+Cl^(-)(s)" "(r)` One of the products is liberated as coloured vapours.D. `Fe_(2)(SO_(4))_(3)+I^(-)rarr" "(s)` In one of the products central atom exhibits its highest oxidation state.
Match the reactions in Column I with nature of the reactions `//` type of the products in Column II. A. `O_(2)^(-)rarrO_(2)+O_(2)^(2)" "(p)` redox reactionB. `CrO_(4)^(2-)+H^(+)rarr" "(q)` One of the products has trigonal planar structureC. `MnO_(4)^(-)+NO_(2)^(-)+H^(+)rarr" "(r )` dimeric bridged tetrahdedral metal ionD. `NO_(3)^(-)+H_(2)SO_(4)+Fe^(2+)rarr" "(s)` disproportionation
Zn reacts with cold and very dil `HNO_(3)` to giveA. `NH_(4)NO_(3)`B. `N_(2)O`C. `NO`D. `NO_(2)`
`underset(("Purple"))(A)rarrunderset(("Green"))(B)+underset(("Black"))(C)+underset(("Gas"))(D)` B cannot be converted to A byA. `KOH`B. `CO_(2)` is formedC. `Cl_(2)`D. `O_(2)`

In solid `CuSO_(4).5H_(2)O`A. `Cu^(2+)` ion is coordinate bonded to four water moleculesB. One `H_(2)O` molecule is `H-` bondedC. It has four types of bonds, Ionic, covalent, coordinate and H- bondD. Five molecules of `H_(2)O` are coordinate bonded to `Cu^(2+)`

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment