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In the above question, the resultant upward force exerted by the sides of the glass on the water is

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> N<br/>102 N<br/>303 N<br/>211 N</p>Solution :Force exerted by atmosphere on <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> is <br/> `F_(2)=(P_(a))A_(2)=(1.01xx10^(5))xx(<a href="https://interviewquestions.tuteehub.com/tag/3xx10-1865443" style="font-weight:bold;" target="_blank" title="Click to know more about 3XX10">3XX10</a>^(-3)) =303 N` (downwards) <br/> Force exerted by bottom on the water, <br/> `F_(3)=-F_(1)=102 N` (downwards) <br/> Let F be the force exerted by side walls on <a href="https://interviewquestions.tuteehub.com/tag/thwe-3217457" style="font-weight:bold;" target="_blank" title="Click to know more about THWE">THWE</a> water (upwards) there <a href="https://interviewquestions.tuteehub.com/tag/equilibrium-974342" style="font-weight:bold;" target="_blank" title="Click to know more about EQUILIBRIUM">EQUILIBRIUM</a> of water : net upward force = net downward force <br/> or `F+F_(3)=F_(2)+W` <br/> `:.F=F_(2)+W-f_(3)=303+10-102=211 N` (downwards)</body></html>


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