1.

In the adjoining figure, M is the centre of the circle and seg AB is a diameter, seg MS ⊥ chord AD, seg MT ⊥ chord AC, ∠DAB ≅ ∠CAB. i. Prove that: chord AD ≅ chord AC. ii. To solve this problem which theorems will you use? a. The chords which are equidistant from the centre are equal in length.b. Congruent chords of a circle are equidistant from the centre.iii. Which of the following tests of congruence of triangles will be useful?a. SAS b. ASA c. SSS d. AAS e. Hypotenuse-side test. Using appropriate test and theorem write the proof of the above example.

Answer»

Proof:

i. ∠DAB ≅ ∠CAB [Given] 

∴ ∠SAM ≅ ∠TAM (i) [A – S – D, A – M – B, A -T – C] 

In ∆SAM and ∆TAM, 

∠SAM ≅ ∠TAM [From (i)] 

∠ASM ≅ ∠ATM [Each angle is of measure 90°] 

seg AM ≅ seg AM [Common side]

∴ ∆SAM ≅ ∆TAM [AAS [SAA] test of congruency] 

∴ side MS ≅ side MT [c.s.c.t] 

But, seg MS ⊥ chord AD [Given] 

seg MT ⊥chord AC

∴ chord AD ≅ chord AC [Chords of a circle equidistant from the centre are congruent]

ii. Theorem used for solving the problem: 

The chords which are equidistant from the centre are equal in length. 

iii. Test of congruency useful in solving the above problem is AAS ISAAI test of congruency.



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