In the circuit shown in figure, E1 and E2 are two ideal sources of unknown emfs. Current flowing through resistor of resistance R Ω is 2 A and through resistor of resistance 4 Ω is 3 A as shown. If potential difference across 6 Ω resistance is VA−VB=10 V, then the value of (E2−E1)R( in V.Ω) is

In the circuit shown in figure, E1 and E2 are two ideal sources of unk

1.	In the circuit shown in figure, E1 and E2 are two ideal sources of unknown emfs. Current flowing through resistor of resistance R Ω is 2 A and through resistor of resistance 4 Ω is 3 A as shown. If potential difference across 6 Ω resistance is VA−VB=10 V, then the value of (E2−E1)R( in V.Ω) is
Answer» In the circuit shown in figure, $E_{1}$ and $E_{2}$ are two ideal sources of unknown emfs. Current flowing through resistor of resistance $R Ω$ is $2 A$ and through resistor of resistance $4 Ω$ is $3 A$ as shown. If potential difference across $6 Ω$ resistance is $V_{A} - V_{B} = 10 V$ , then the value of $(E_{2} - E_{1}) R$ ( in $V . Ω$ ) is

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