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In the circuit shown in figure Find the potential differnece across capacitor. |
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Answer» When capacitor is fully charged, it fraws no currnet, and hence provides infinite resistance, then no current flows in arm EF. The potential difference across C and F. The resistance of arm AD and they together are in series with resistance of arm DF. The effective resistance between A and F of circuit is, `R = (3xx6/3+6) + 3 = 2 +3 =5 Omega` Main in the circuit, `i = 15/5=3 A` Current through arm BCD ` = 1 xx 3/6+3 = 3xx3/9 = 1 A` Potential difference across C and D `= 1 xx 3 = 3V` Current through arm DF, i =3A Potential differences across D and F `= 3 xx 3 = 9 V` So, potential difference across C and F `= 3+ 9=12 V` Thus, potential difference across the capacitor is 12 V |
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