InterviewSolution
Saved Bookmarks
| 1. |
In the circuit shown in figure, the current is to measured. What is the value of the current if the ammeter shown (i) is a galvanometer with a resistance `R_G=60*00Omega`. (ii) is a galvanometer described in (i) but converted to an ammeter by a shunt resistance `r_s=0*02Omega`, (iii) is an ideal ammeter with zero resistance? |
|
Answer» Let G be the resistance of ammeter (i.e. galvanometer). Then current in the circuit, `I=(epsilon)/(R+G)=(3*00)/(3*00+60*00)=0*048A`. (ii) When the ammeter (i.e., galvanometer) is shunted with resistance S, its effective resistance, `R_p=(GS)/(G+S)=(60xx0*02)/(60+0*02)~~0*02Omega` Current in the circuit, `I=(epsilon)/(R+R_p)=(3*00)/(3*00+*02)~~0*99A`. (iii) For the ideal ammeter with zero resistance current, `I=(3*00)/(3*00)=1*00A`. |
|