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In the circuit shown in the adjacent figure A. the potential at `P` is `-7.5V`B. the potential at `Q` is `-1V`C. the potential at `R` is zeroD. the potential at `S` is zero |
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Answer» The current in the circuit `I=((20-10))/((7.5+.5+1+1))=(10)/(10)=1Amp` The potential difference across `PS V_(PS)=7.5xx1=7.5V` The potential difference across `Q R`, `V_(QR)=1xx1=1V` As point `G` is connected to earth hence potentials of `R` and `S` is zero. The direction of the current in the circuit is from `P` to `S`, hence point `P` is at higher potential. `:. V_(p)=7.5V` similarly `V_(Q)= -1V` |
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