InterviewSolution
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InterviewSolution
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In the circuit shown in the figure, there are two parallel plate capacitors each of capacitance C. The switch `S_1` is pressed first to fully charge the capacitor `C_1` and then released. The switch `S_2` is then pressed to charge the capacitor `C_2`. After some time, `S_2` is released and then `S_3` is pressed. After some time A. (a) The charge on the upper plate of `C_1` is `2CV_0`B. (b) The charge on the upper plate of `C_1` is `CV_0`C. (c) The charge on the upper plate of `C_2` is 0D. (d) The charge on the upper plate of `C_2` is `-CV_0` |
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Answer» Correct Answer - B::D Step1: When `S_1` is pressed. The capacitor `C_1` gets charged such that its upper plate acquires a positive charge `+2CV_0` and lower plate `-2CV_0`. Step 2: When `S_2` is pressed (`S_1` open). As `C_1=C_2` the charge gets distributed equal. The upper plates of `C_1` and `C_2` now take charge `+CV_0` each and lower plate `-CV_0` each. (b) and (d) are correct option. |
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