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In the cricket game, a batsman strikes the ball such that it moves with the speed 30ms^(-1) at an angle 30^(@) with the horizontal as shown in the figure. The boundary line of the cricket ground is located at a distance of 75 m from the batsman? Will the ball go for a six? (Neglect the air resistance and take acceleration due to gravity g=10ms^(-2).

Answer» <html><body><p></p>Solution :The motion of the cricket ball in air is essentially a projectile motion. As we have already seen, the range (horizontal distance) of the projectile motion is given by <br/> `R=(u^(2)<a href="https://interviewquestions.tuteehub.com/tag/sin2theta-3032597" style="font-weight:bold;" target="_blank" title="Click to know more about SIN2THETA">SIN2THETA</a>)/(g)` <br/> The <a href="https://interviewquestions.tuteehub.com/tag/initial-499269" style="font-weight:bold;" target="_blank" title="Click to know more about INITIAL">INITIAL</a> speed `u=30ms^(-1)` <br/> The <a href="https://interviewquestions.tuteehub.com/tag/projection-1169328" style="font-weight:bold;" target="_blank" title="Click to know more about PROJECTION">PROJECTION</a> angle `theta=30^(@)` <br/> The horizontal distance travelled by the cricket ball <br/> `R=((30)^(2)xxsin60^(@))/(10)=(900xx(sqrt3)/(2))/(10)=77.94m` <br/> This distance is greater than the distance of the <a href="https://interviewquestions.tuteehub.com/tag/boundary-401242" style="font-weight:bold;" target="_blank" title="Click to know more about BOUNDARY">BOUNDARY</a> <a href="https://interviewquestions.tuteehub.com/tag/line-1074199" style="font-weight:bold;" target="_blank" title="Click to know more about LINE">LINE</a>. Hence the ball will cross this line and go for a six. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_PHY_XI_V01_C07_SLV_034_S01.png" width="80%"/></body></html>


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