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In the electrochemical reaction, `2Fe^(3+)+Zn rarr Zn^(2+) + 2Fe^(2+)` increasing the concentration of `Fe^(2+)`:A. increasing cell emfB. increasing the current flowC. decreases the cell emfD. alters the pH of the solution . |
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Answer» Correct Answer - C `E_("cell") = E_("cell")^(@) - (RT)/(nF) "ln" ([Fe^(2+)]^(2))/([Fe^(3+)]^(2))` . Increasing `[Fe^(2+)]` decreases `E_("cell")` . |
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