InterviewSolution
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InterviewSolution
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In the Ellingham diagram, for the formation of carbon monoxide(a) \(\Big(\frac{\Delta\,S^0}{\Delta\,T}\Big)\) is negative(b) \(\Big(\frac{\Delta\,G^0}{\Delta\,T}\Big)\) is positive(c) \(\Big(\frac{\Delta\,G^0}{\Delta\,T}\Big)\)is negative(d) initially \(\Big(\frac{\Delta\,T}{\Delta\,G^0}\Big)\) is positive, after 700°C \(\Big(\frac{\Delta\,G^0}{\Delta\,T}\Big)\) is negative |
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Answer» (c) \(\Big(\frac{\Delta\,G^0}{\Delta\,T}\Big)\)is negative |
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